1. The problem involves understanding the division expressions given: \n\nFirst division: divisor = 2, quotient = 2, dividend = a - 1 2 (likely meaning a - 12)\n\nSecond division: divisor = 4, quotient = 4, dividend = a + 29 - 3\n\n2. We use the division formula: $$\text{Dividend} = \text{Divisor} \times \text{Quotient} + \text{Remainder}$$\n\n3. For the first division, assuming no remainder, we have: $$a - 12 = 2 \times 2 = 4$$\n\n4. Solve for $a$: $$a - 12 = 4 \implies a = 4 + 12 = 16$$\n\n5. For the second division, assuming no remainder, simplify the dividend: $$a + 29 - 3 = a + 26$$\n\n6. Using the division formula: $$a + 26 = 4 \times 4 = 16$$\n\n7. Solve for $a$: $$a + 26 = 16 \implies a = 16 - 26 = -10$$\n\n8. We have two values for $a$ from the two divisions: $16$ and $-10$. Since $a$ must be consistent, check if the problem expects a single $a$ or separate values.\n\nFinal answer:\n- From first division: $a = 16$\n- From second division: $a = -10$