1. Problem 1: Loremea received a 5% discount which saved her ₱634.50. We need to find the original price (let's call it $P$). Discount = 5% of original price = $0.05P$ Given discount = 634.50, so $$0.05P = 634.50$$ Divide both sides by 0.05: $$P = \frac{634.50}{0.05} = 12690$$ Original price is ₱12690. 2. Problem 2: Tuition fee is ₱23 990 and discount given is ₱3 838.40. We need to find the discount rate in percentage. Discount rate = $\frac{Discount}{Total\ fee} \times 100$ $$\text{Discount rate} = \frac{3838.40}{23990} \times 100 = 16\%$$ The discount rate is 16%. 3. Problem 3: The sale price of the printer is ₱12 241.25 after a 12.5% discount. We need the original price $P$. Sale price = Original price - discount Discount = 12.5% of $P$ = $0.125P$ Therefore: $$Sale = P - 0.125P = 0.875P$$ Given sale price: $$0.875P = 12241.25$$ Divide both sides by 0.875: $$P = \frac{12241.25}{0.875} = 13990$$ Original price is ₱13990. 4. Problem 4: Isaac wants a 17.5% profit on a bracelet bought at ₱15 990. We want the selling price. Profit = 17.5% of ₱15 990 = $0.175 \times 15990 = 2798.25$ Selling price = Cost price + Profit = 15990 + 2798.25 = 18788.25 Isaac should sell the bracelet for ₱18788.25. 5. Problem 5: The markup price is ₱175.50, which is 18% of the original price $P$. $$0.18P = 175.50$$ Divide both sides by 0.18: $$P = \frac{175.50}{0.18} = 975$$ The original price is ₱975.