1. **State the problem:** We need to find how much total damage the gun deals in 6 seconds. Given data: damage per magazine = 10576, damage per shot = 5288, reload speed = 1.5 seconds, fire rate = 67 rounds per minute (rpm). 2. **Convert fire rate to shots per second:** $$\text{fire rate} = 67 \text{ rpm} = \frac{67}{60} \text{ shots per second} \approx 1.1167 \text{ shots/second}$$ 3. **Calculate shots fired in 6 seconds:** $$\text{shots in 6s} = 1.1167 \times 6 = 6.7 \text{ shots}$$ Since partial shots aren’t possible, consider the integer part: 6 shots. 4. **Check if reload occurs within 6 seconds:** One magazine has 2 shots (since damage per magazine is 10576 and damage per shot is 5288, shots per magazine = $$\frac{10576}{5288} = 2$$). In 6 seconds, we need to fire 6 shots which is more than one magazine capacity (2 shots). Thus, reload(s) will occur. 5. **Calculate total reloads in 6 seconds:** The gun fires 2 shots, then reloads in 1.5 seconds. Number of shots possible before needing reload is 2. Time to fire 2 shots: Each shot interval is $$\frac{60}{67} \approx 0.8955$$ seconds. Total time to fire 2 shots (including intervals) is approximately: $$0.8955 \times (2-1) = 0.8955 \text{ seconds}$$ (time between shots) Total time for 2 shots + reload: $$0.8955 + 1.5 = 2.3955 \text{ seconds}$$ Number of full cycles (2 shots + reload) in 6 seconds: $$\frac{6}{2.3955} \approx 2.504$$ So, 2 full cycles with some extra time left. 6. **Calculate total shots fired:** Each cycle fires 2 shots, so 2 cycles give 4 shots. Remaining time after 2 cycles: $$6 - 2 \times 2.3955 = 1.209 \text{ seconds}$$ In this time, number of shots possible (intervals of 0.8955s): Can fire 1 more shot (as 1 shot takes 0 seconds initially and next shot after 0.8955 seconds). Total shots fired: $$4 + 1 = 5$$ shots. 7. **Calculate total damage:** Total damage = number of shots fired $$\times$$ damage per shot = $$5 \times 5288 = 26440$$. **Final answer:** The gun deals total damage of $$26440$$ in 6 seconds.