1. The problem states we have the curve defined by the function $$y = -x^2 + 5$$ and we want to find where the point at $$x = 3$$ lies on this curve. 2. To find the corresponding $$y$$-value when $$x = 3$$, substitute $$3$$ into the equation: $$y = -(3)^2 + 5$$ 3. Simplify the expression: $$y = -9 + 5 = -4$$ 4. So the coordinate point on the curve at $$x = 3$$ is $$ (3, -4) $$. 5. From the graph description, points A and D are both at approximately $$(3, -4)$$. 6. Therefore, the correct points to plot for $$x = 3$$ on the curve $$y = -x^2 + 5$$ are points A and D.