Cube Root Fraction 5Ccabc
1. **State the problem:** Simplify the cube root of the fraction $\frac{27}{8}$, written as $\sqrt[3]{\frac{27}{8}}$.
2. **Recall the property of cube roots:** The cube root of a fraction is the fraction of the cube roots, i.e.,
$$\sqrt[3]{\frac{a}{b}} = \frac{\sqrt[3]{a}}{\sqrt[3]{b}}$$
3. **Apply the property:**
$$\sqrt[3]{\frac{27}{8}} = \frac{\sqrt[3]{27}}{\sqrt[3]{8}}$$
4. **Evaluate the cube roots:**
- $\sqrt[3]{27} = 3$ because $3^3 = 27$
- $\sqrt[3]{8} = 2$ because $2^3 = 8$
5. **Write the simplified fraction:**
$$\frac{3}{2}$$
6. **Check the answer choices:** The simplified form $\frac{3}{2}$ matches the third option.
**Final answer:** $\frac{3}{2}$