1. **State the problem:** We are given total Covid-19 cases in Egypt on two dates: July 24, 2020 (91,072 cases) and August 3, 2020 (94,640 cases). We assume the number of cases changes linearly over time. We want to find the total cases on August 9, 2020. 2. **Define variables:** Let $x$ be the number of days since July 24, 2020. Then: - On July 24, $x=0$, cases $= 91072$ - On August 3, $x=10$ (since July has 31 days, August 3 is 10 days after July 24), cases $= 94640$ 3. **Find the linear function:** The number of cases $C(x)$ changes linearly, so: $$C(x) = mx + b$$ where $m$ is the rate of change (slope) and $b$ is the initial value at $x=0$. 4. **Calculate slope $m$:** $$m = \frac{C(10) - C(0)}{10 - 0} = \frac{94640 - 91072}{10} = \frac{3568}{10} = 356.8$$ 5. **Find $b$:** Since $C(0) = 91072$, we have $b = 91072$. 6. **Write the equation:** $$C(x) = 356.8x + 91072$$ 7. **Find cases on August 9:** August 9 is 16 days after July 24 ($x=16$), so: $$C(16) = 356.8 \times 16 + 91072 = 5708.8 + 91072 = 96780.8$$ 8. **Final answer:** The total cases on August 9, 2020, are approximately $96781$ (rounding to the nearest whole number).