Consecutive Odd Numbers 0Da717
1. **Problem statement:** We are given 6 consecutive odd numbers whose sum is 204. We need to find the fourth number in this sequence.
2. **Formula and approach:** Let the first odd number be $x$. Since the numbers are consecutive odd numbers, the sequence can be written as:
$$x, x+2, x+4, x+6, x+8, x+10$$
The sum of these 6 numbers is given by:
$$x + (x+2) + (x+4) + (x+6) + (x+8) + (x+10) = 204$$
3. **Simplify the sum:**
$$6x + (2 + 4 + 6 + 8 + 10) = 204$$
Calculate the sum inside the parentheses:
$$2 + 4 + 6 + 8 + 10 = 30$$
So,
$$6x + 30 = 204$$
4. **Solve for $x$:**
$$6x = 204 - 30$$
$$6x = 174$$
$$x = \frac{174}{6} = 29$$
5. **Find the fourth number:**
The fourth number is:
$$x + 6 = 29 + 6 = 35$$
**Final answer:** The fourth number in the sequence is **35**.