1. **State the problem:** We are given 6 consecutive integers whose sum is 393, and we need to find the third number in this sequence. 2. **Set up variables:** Let the first integer be $x$. Then the six consecutive integers are: $$x, x+1, x+2, x+3, x+4, x+5$$ 3. **Write the sum equation:** The sum of these integers is given as 393, so: $$x + (x+1) + (x+2) + (x+3) + (x+4) + (x+5) = 393$$ 4. **Simplify the equation:** Combine like terms: $$6x + (1+2+3+4+5) = 393$$ $$6x + 15 = 393$$ 5. **Solve for $x$:** $$6x = 393 - 15$$ $$6x = 378$$ $$x = \frac{378}{6} = 63$$ 6. **Find the third number:** The third number is $x+2$: $$63 + 2 = 65$$ **Final answer:** The third number in the sequence is **65**.