1. State the problem: Solve the quadratic equation $$2x^2-8x+8=0$$ using the complete the square method. 2. Divide the entire equation by 2 to simplify: $$x^2 - 4x + 4 = 0$$. 3. Move the constant term to the right side: $$x^2 - 4x = -4$$. 4. Complete the square by adding $$\left(\frac{-4}{2}\right)^2 = (-2)^2 = 4$$ to both sides: $$x^2 - 4x + 4 = -4 + 4$$ 5. Simplify the right side: $$x^2 - 4x + 4 = 0$$. 6. Recognize that the left side is a perfect square: $$(x - 2)^2 = 0$$. 7. Take the square root of both sides: $$x - 2 = 0$$. 8. Solve for $$x$$: $$x = 2$$. Final answer: The solution to the equation is $$x = 2$$.