1. We are given a ratio table with two columns where the left column values correspond to the right column values. 2. The table provided is: | Left (x) | Right (y) | |----------|------------| | 8 | 1 | | 40 | 5 | | 64 | 8 | | 88 | ? | | 96 | ? | 3. First, observe that the ratio between corresponding values in the pairs seems consistent across the first three rows. 4. Calculate the ratio factor using the first row: $$ \text{ratio} = \frac{y}{x} = \frac{1}{8} = 0.125 $$ 5. Verify with the second and third rows: For 40 and 5: $$\frac{5}{40} = 0.125$$ For 64 and 8: $$\frac{8}{64} = 0.125$$ The ratio is consistent. 6. Use the same ratio to find the missing values for 88 and 96. For 88: $$ y = 88 \times 0.125 = 11 $$ For 96: $$ y = 96 \times 0.125 = 12 $$ 7. So, the completed table is: | Left (x) | Right (y) | |----------|------------| | 8 | 1 | | 40 | 5 | | 64 | 8 | | 88 | 11 | | 96 | 12 | 8. In conclusion, the missing values in the right column are 11 and 12 for 88 and 96 respectively, maintaining the constant ratio $$\frac{y}{x} = 0.125$$.