Clean Unclean Ratio 928B57
1. **State the problem:** Sana cleaned $\frac{1}{4}$ of her house, and her sister cleaned $\frac{1}{5}$ of the remaining part. We need to find the ratio of the clean part to the unclean part of the house.
2. **Identify the total and parts cleaned:**
- Total house = 1 (whole)
- Sana cleaned $\frac{1}{4}$
- Remaining after Sana cleaned = $1 - \frac{1}{4} = \frac{3}{4}$
3. **Calculate the part cleaned by sister:**
- Sister cleaned $\frac{1}{5}$ of the remaining $\frac{3}{4}$
- So, sister cleaned $\frac{1}{5} \times \frac{3}{4} = \frac{3}{20}$
4. **Calculate total cleaned:**
- Total cleaned = Sana's part + Sister's part = $\frac{1}{4} + \frac{3}{20}$
- Find common denominator 20: $\frac{5}{20} + \frac{3}{20} = \frac{8}{20} = \frac{2}{5}$
5. **Calculate unclean part:**
- Unclean = Total - Cleaned = $1 - \frac{2}{5} = \frac{3}{5}$
6. **Find ratio of clean to unclean:**
- Ratio = Clean : Unclean = $\frac{2}{5} : \frac{3}{5}$
- Simplify by multiplying both sides by 5: $2 : 3$
**Final answer:** The ratio of clean to unclean parts of the house is $2 : 3$.