Subjects algebra

Chickens Goats B3Da6E

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Chickens Goats B3Da6E


1. **State the problem:** Old McDonald has 250 chickens and goats. The total number of feet is 760. We need to find how many chickens and goats there are. 2. **Understand and devise a plan:** - Let $c$ be the number of chickens and $g$ be the number of goats. - Chickens have 2 feet each, goats have 4 feet each. - We have two equations: $$c + g = 250$$ $$2c + 4g = 760$$ 3. **Carry out the plan:** - From the first equation, express $c$ as $c = 250 - g$. - Substitute into the second equation: $$2(250 - g) + 4g = 760$$ $$500 - 2g + 4g = 760$$ $$500 + 2g = 760$$ $$2g = 760 - 500 = 260$$ $$g = 130$$ - Substitute $g=130$ back to find $c$: $$c = 250 - 130 = 120$$ 4. **Look back and check:** - Total feet check: $2 imes 120 + 4 imes 130 = 240 + 520 = 760$ correct. - Total animals check: $120 + 130 = 250$ correct. **Answer:** Old McDonald has 120 chickens and 130 goats.