1. **Stating the problem:** We have three people A, B, and C with cherries. Given: - A + B + C = 96 - A + B = 63 - B + C = 60 We need to find: - Who has the most cherries? - How many cherries does that person have? - Who has the fewest cherries? - If cherries were shared equally, how many would A give to B and how many would C give to B? 2. **Using the formulas and rules:** From the equations: $$A + B + C = 96$$ $$A + B = 63$$ $$B + C = 60$$ We can find each person's cherries by substitution. 3. **Finding C:** Subtract the second equation from the first: $$ (A + B + C) - (A + B) = 96 - 63 $$ $$ C = 33 $$ 4. **Finding A:** Subtract the third equation from the first: $$ (A + B + C) - (B + C) = 96 - 60 $$ $$ A = 36 $$ 5. **Finding B:** Use the second equation: $$ A + B = 63 $$ $$ 36 + B = 63 $$ $$ B = 27 $$ 6. **Who has the most cherries?** A has 36, B has 27, C has 33. So, A has the most cherries. 7. **Who has the fewest cherries?** B has the fewest cherries (27). 8. **Sharing cherries equally:** Total cherries = 96 Each person gets: $$ \frac{96}{3} = 32 $$ 9. **How many would A give to B?** A has 36, needs to give to B who has 27: $$ 36 - 32 = 4 $$ A gives 4 cherries to B. 10. **How many would C give to B?** C has 33, needs to give to B: $$ 33 - 32 = 1 $$ C gives 1 cherry to B. Final answers: 81. A 82. 36 83. B 84. 4 85. 1