1. The problem states that a human blinks approximately $8 \times 10^{6}$ times in 1 year. 2. We need to find the total blinks in 3 years, so we'll multiply the yearly blinks by 3. 3. Calculate: $$3 \times (8 \times 10^{6}) = (3 \times 8) \times 10^{6} = 24 \times 10^{6}.$$ 4. Write the result in standard form. $24 \times 10^{6} = 2.4 \times 10^{7}$ because $24 = 2.4 \times 10^{1}$ and adding the exponents: $10^{1} \times 10^{6} = 10^{7}$. 5. Therefore, a human blinks approximately $2.4 \times 10^{7}$ times in 3 years.