1. The problem asks to find the equation of the axis of symmetry of the parabola given by the equation $$y = x^2 - 6$$. 2. Recall that for a parabola in the form $$y = ax^2 + bx + c$$, the axis of symmetry is a vertical line given by the formula $$x = -\frac{b}{2a}$$. 3. In the given equation, $$y = x^2 - 6$$, we identify $$a = 1$$, $$b = 0$$, and $$c = -6$$. 4. Substitute $$a$$ and $$b$$ into the formula for the axis of symmetry: $$x = -\frac{0}{2 \times 1} = 0$$. 5. Therefore, the axis of symmetry is the vertical line $$x = 0$$. This matches the vertex at (0, -6) and confirms the axis of symmetry passes through the vertex.