1. The problem asks for the axis of symmetry of the curve given by the quadratic function $y = 3x^2 - x - 4$. 2. Recall that the axis of symmetry for a quadratic function in the form $y = ax^2 + bx + c$ is given by the formula: $$x = -\frac{b}{2a}$$ 3. Identify the coefficients from the equation: - $a = 3$ - $b = -1$ 4. Substitute $a$ and $b$ into the formula: $$x = -\frac{-1}{2 \times 3} = \frac{1}{6}$$ 5. Therefore, the axis of symmetry is the vertical line: $$x = \frac{1}{6}$$ This line divides the parabola into two mirror-image halves.