Subjects algebra

Average Length Width Ec674F

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Average Length Width Ec674F


1. **State the problem:** We need to find the average length and average width per box from the given sums of lengths and widths. 2. **Identify the data:** Each entry in LENGTH and WIDTH columns is a sum of four numbers representing measurements for four boxes. 3. **Calculate the total length and total width for each row by summing the numbers:** For example, for the first LENGTH row: $3.6 + 8 + 13.6 + 22.5 = 47.7$ For the first WIDTH row: $1.1 + 1.3 + 1.2 + 1.2 = 4.8$ 4. **Calculate the average length and width per box for each row by dividing the total by 4 (since there are 4 boxes per row):** Average length = $\frac{\text{total length}}{4}$ Average width = $\frac{\text{total width}}{4}$ 5. **Perform calculations for all rows:** - Row 1 LENGTH: $3.6+8+13.6+22.5=47.7$, average length = $\frac{47.7}{4}=11.925$ - Row 1 WIDTH: $1.1+1.3+1.2+1.2=4.8$, average width = $\frac{4.8}{4}=1.2$ - Row 2 LENGTH: $3.1+6.4+14.5+25.2=49.2$, average length = $12.3$ - Row 2 WIDTH: $8+1.3+1.4+1.5=12.2$, average width = $3.05$ - Row 3 LENGTH: $3.5+8.6+14.9+24.4=51.4$, average length = $12.85$ - Row 3 WIDTH: $1.2+1.2+1.1+1.5=5.0$, average width = $1.25$ - Row 4 LENGTH: $9.7+17.4+23.5=50.6$, average length = $\frac{50.6}{3}\approx16.867$ - Row 4 WIDTH: $1.1+1.3+1.7=4.1$, average width = $\frac{4.1}{3}\approx1.367$ - Row 5 LENGTH: $4.8+11.1+17.1+28.6=61.6$, average length = $15.4$ - Row 5 WIDTH: $1.4+1.3+5.1+1.7=9.5$, average width = $2.375$ - Row 6 LENGTH: $2.2+5.3+10.5+19.4=37.4$, average length = $9.35$ - Row 6 WIDTH: $1.2+1.3+1.1+1.2=4.8$, average width = $1.2$ - Row 7 LENGTH: $3.1+7.4+14.2+33.8=58.5$, average length = $14.625$ - Row 7 WIDTH: $1.4+1.3+1.5+1.5=5.7$, average width = $1.425$ - Row 8 LENGTH: $2.7+6.1+12.4=21.2$, average length = $\frac{21.2}{3}\approx7.067$ - Row 8 WIDTH: $0.7+0.8+0.9=2.4$, average width = $0.8$ - Row 9 LENGTH: $5.4+14+22.3+30.2=71.9$, average length = $17.975$ - Row 9 WIDTH: $1.1+1.3+1.4+1.8=5.6$, average width = $1.4$ - Row 10 LENGTH: $4.3+9.1+15.8+24.7=53.9$, average length = $13.475$ - Row 10 WIDTH: $1.4+1.4+1.4+1.5=5.7$, average width = $1.425$ - Row 11 LENGTH: $2.7+6.7+10.4=19.8$, average length = $6.6$ - Row 11 WIDTH: $1.1+1+0.9=3.0$, average width = $1.0$ - Row 12 LENGTH: $4.5+12.1+20.5+31.9=69.0$, average length = $17.25$ - Row 12 WIDTH: $1.9+1.2+1.4+1.7=6.2$, average width = $1.55$ - Row 13 LENGTH: $4.9+11.6+19.8+32.3=68.6$, average length = $17.15$ - Row 13 WIDTH: $1.6+1.7+1.4+1.9=6.6$, average width = $1.65$ - Row 14 LENGTH: $4.6+9.9+20.1+26.9=61.5$, average length = $15.375$ - Row 14 WIDTH: $1.7+1.3+1.2+1.6=5.8$, average width = $1.45$ - Row 15 LENGTH: $9.9+13.5+19.1=42.5$, average length = $14.167$ - Row 15 WIDTH: $1+1.2+1.6=3.8$, average width = $1.267$ - Row 16 LENGTH: $4.3+10.5+16.9+30.1=61.8$, average length = $15.45$ - Row 16 WIDTH: $1.5+1.3+1.1+1.6=5.5$, average width = $1.375$ 6. **Final answer:** The average length and width per box for each row are calculated as above.