Arithmetic Sequence Ffa68E
1. **Stating the problem:**
We are given an arithmetic sequence defined by terms involving $P$ and $E$, specifically the terms $P$, $E$, $1000E$, and $-P$. We need to analyze or find a relationship involving these terms.
2. **Understanding arithmetic sequences:**
An arithmetic sequence is a sequence of numbers where the difference between consecutive terms is constant. This difference is called the common difference $d$.
3. **Setting up the problem:**
Given the terms $a_1 = P$, $a_2 = E$, $a_3 = 1000E$, and $a_4 = -P$, since these are consecutive terms of an arithmetic sequence, the differences between consecutive terms must be equal:
$$a_2 - a_1 = a_3 - a_2 = a_4 - a_3 = d$$
4. **Writing the equations:**
$$E - P = 1000E - E = -P - 1000E$$
Simplify each:
$$E - P = 999E$$
$$999E = -P - 1000E$$
5. **From the first equality:**
$$E - P = 999E \implies -P = 999E - E = 998E \implies P = -998E$$
6. **From the second equality:**
$$999E = -P - 1000E$$
Substitute $P = -998E$:
$$999E = -(-998E) - 1000E = 998E - 1000E = -2E$$
7. **Solve for $E$:**
$$999E = -2E \implies 999E + 2E = 0 \implies 1001E = 0 \implies E = 0$$
8. **Find $P$ using $E=0$:**
$$P = -998E = -998 \times 0 = 0$$
9. **Conclusion:**
The only way for the terms $P$, $E$, $1000E$, and $-P$ to form an arithmetic sequence is if $E=0$ and $P=0$.
**Final answer:**
$$P = 0, \quad E = 0$$