Subjects algebra

Arithmetic Evaluation

Step-by-step solutions with LaTeX - clean, fast, and student-friendly.

Search Solutions

Arithmetic Evaluation


1. Evaluate $24 - (7 + 4)$: Calculate inside parentheses first: $7 + 4 = 11$ Then subtract: $24 - 11 = 13$ 2. Evaluate $3 \times (2^3 - 1) - 17$: Calculate power: $2^3 = 8$ Subtract inside parentheses: $8 - 1 = 7$ Multiply: $3 \times 7 = 21$ Subtract: $21 - 17 = 4$ 3. Evaluate $81 \div (5 + 4)$: Calculate inside parentheses: $5 + 4 = 9$ Divide: $81 \div 9 = 9$ 4. Evaluate $48 - (4 \times 3^2) - 4$: Calculate power: $3^2 = 9$ Multiply: $4 \times 9 = 36$ Subtract stepwise: $48 - 36 = 12$, then $12 - 4 = 8$ 5. Evaluate $7^2 \div 7 + 0 \div 13$: Calculate power: $7^2 = 49$ Divide first term: $49 \div 7 = 7$ Divide second term: $0 \div 13 = 0$ Add: $7 + 0 = 7$ 6. Evaluate $2 \times (2 + 5 + 8) - 24$: Sum inside parentheses: $2 + 5 + 8 = 15$ Multiply: $2 \times 15 = 30$ Subtract: $30 - 24 = 6$ 7. Evaluate $\frac{10^2 - 10}{9} - 9$: Calculate power: $10^2 = 100$ Subtract numerator: $100 - 10 = 90$ Divide: $90 \div 9 = 10$ Subtract: $10 - 9 = 1$ 8. Evaluate $\frac{8 + 2}{10} + 2$: Sum numerator: $8 + 2 = 10$ Divide: $10 \div 10 = 1$ Add: $1 + 2 = 3$ 9. Evaluate $\frac{17 - 5}{22 - 10} + 1$: Subtract numerator: $17 - 5 = 12$ Subtract denominator: $22 - 10 = 12$ Divide: $12 \div 12 = 1$ Add: $1 + 1 = 2$