Algebraic Expression 4B30Cf
1. **State the problem:** Simplify the expression $$\frac{a + b}{a^2 + b^2} - \frac{5a + b}{a^2 - b^2} : \frac{5a^3 + a^2b + 5ab^2 + b^3}{2ab(a - b)}$$
2. **Recall important formulas and rules:**
- Difference of squares: $$a^2 - b^2 = (a - b)(a + b)$$
- Division of fractions: $$\frac{A}{B} : \frac{C}{D} = \frac{A}{B} \times \frac{D}{C}$$
- Factorization and simplification are key.
3. **Rewrite the division as multiplication:**
$$\left(\frac{a + b}{a^2 + b^2} - \frac{5a + b}{a^2 - b^2}\right) \times \frac{2ab(a - b)}{5a^3 + a^2b + 5ab^2 + b^3}$$
4. **Factor denominators and numerator where possible:**
- $$a^2 - b^2 = (a - b)(a + b)$$
- Factor numerator $$5a^3 + a^2b + 5ab^2 + b^3$$ by grouping:
$$5a^3 + a^2b + 5ab^2 + b^3 = a^2(5a + b) + b^2(5a + b) = (a^2 + b^2)(5a + b)$$
5. **Rewrite the expression with factored terms:**
$$\left(\frac{a + b}{a^2 + b^2} - \frac{5a + b}{(a - b)(a + b)}\right) \times \frac{2ab(a - b)}{(a^2 + b^2)(5a + b)}$$
6. **Find common denominator for the subtraction inside parentheses:**
Common denominator is $$(a^2 + b^2)(a - b)(a + b)$$ but note $a^2 + b^2$$ and $$(a - b)(a + b) = a^2 - b^2$$ are different, so keep as is.
Rewrite subtraction:
$$\frac{(a + b)(a - b)(a + b)}{(a^2 + b^2)(a - b)(a + b)} - \frac{(5a + b)(a^2 + b^2)}{(a^2 + b^2)(a - b)(a + b)}$$
But this is complicated; better to write as:
$$\frac{(a + b)(a - b)(a + b) - (5a + b)(a^2 + b^2)}{(a^2 + b^2)(a - b)(a + b)}$$
7. **Simplify numerator of subtraction:**
- $$(a + b)(a - b)(a + b) = (a + b)^2 (a - b)$$
- Expand $$(a + b)^2 = a^2 + 2ab + b^2$$
- So numerator is:
$$ (a^2 + 2ab + b^2)(a - b) - (5a + b)(a^2 + b^2) $$
8. **Expand both parts:**
- First part:
$$ (a^2 + 2ab + b^2)(a - b) = a^3 - a^2b + 2a^2b - 2ab^2 + ab^2 - b^3 = a^3 + a^2b - ab^2 - b^3 $$
- Second part:
$$ (5a + b)(a^2 + b^2) = 5a^3 + 5ab^2 + a^2b + b^3 $$
9. **Subtract second part from first:**
$$ (a^3 + a^2b - ab^2 - b^3) - (5a^3 + 5ab^2 + a^2b + b^3) = a^3 - 5a^3 + a^2b - a^2b - ab^2 - 5ab^2 - b^3 - b^3 = -4a^3 - 6ab^2 - 2b^3 $$
10. **Rewrite the entire expression:**
$$ \frac{-4a^3 - 6ab^2 - 2b^3}{(a^2 + b^2)(a - b)(a + b)} \times \frac{2ab(a - b)}{(a^2 + b^2)(5a + b)} $$
11. **Cancel common factors:**
- Cancel $$(a - b)$$
- Expression becomes:
$$ \frac{-4a^3 - 6ab^2 - 2b^3}{(a^2 + b^2)(a + b)} \times \frac{2ab}{(a^2 + b^2)(5a + b)} $$
12. **Factor numerator $$-4a^3 - 6ab^2 - 2b^3$$:**
Factor out $$-2$$:
$$ -2(2a^3 + 3ab^2 + b^3) $$
13. **Final expression:**
$$ \frac{-2(2a^3 + 3ab^2 + b^3) \times 2ab}{(a^2 + b^2)^2 (a + b)(5a + b)} = \frac{-4ab(2a^3 + 3ab^2 + b^3)}{(a^2 + b^2)^2 (a + b)(5a + b)} $$
This is the simplified form.
**Final answer:**
$$\boxed{\frac{-4ab(2a^3 + 3ab^2 + b^3)}{(a^2 + b^2)^2 (a + b)(5a + b)}}$$