1. Stating the problem: The number of girls appearing for the test is twice the number of boys. Let the number of boys be $B$ and the number of girls be $G=2B$. 2. Admission rates: 30% of girls get admission, so admitted girls = $0.3 \times G = 0.3 \times 2B = 0.6B$. 3. Similarly, 45% of boys get admission, so admitted boys = $0.45 \times B = 0.45B$. 4. Total students = $B + G = B + 2B = 3B$. 5. Total admitted students = admitted girls + admitted boys = $0.6B + 0.45B = 1.05B$. 6. Number of students not admitted = total students - admitted students = $3B - 1.05B = 1.95B$. 7. Percentage of students not admitted = $\frac{1.95B}{3B} \times 100 = 65\%$. 8. Answer matches option D.