Absolute Inequality 8Da126
1. **Problem statement:** Given the inequality $16 > |12 - 4x|$, find the solution set.
2. **Recall the definition of absolute value inequality:** For $a > |b|$, this means $-a < b < a$.
3. **Apply this to the inequality:**
$$16 > |12 - 4x| \implies -16 < 12 - 4x < 16$$
4. **Solve the compound inequality:**
- From $-16 < 12 - 4x$:
$$-16 - 12 < -4x \implies -28 < -4x \implies 7 > x$$
- From $12 - 4x < 16$:
$$-4x < 4 \implies x > -1$$
5. **Combine the two inequalities:**
$$-1 < x < 7$$
6. **Final solution set:**
$$(-1, 7)$$
**Note:** The options given do not match this solution exactly, so the correct answer is the interval $(-1,7)$.