Problem: Compute $0.02^3\times10^{-1}$.\n\n1. Rewrite the number in scientific notation: $0.02=2\times10^{-2}$.\n\n2. Cube the scientific form: $(2\times10^{-2})^3 = 2^3 \times (10^{-2})^3 = 8\times10^{-6}$.\n\n3. Multiply by $10^{-1}$: $8\times10^{-6}\times10^{-1} = 8\times10^{-7}$.\n\n4. Convert to decimal form: $8\times10^{-7}=0.0000008$.\n\n5. Final answer: $0.0000008$ or $8\times10^{-7}$.\n