1. **Problem 1:** Erin takes photos of size 3.6 MB each. How many photos can she store on a 1 GB memory card? 2. **Problem 2:** Sue has a 32 GB memory card and wants to store about 13000 photos. What photo size should she use? --- ### Problem 1: Number of photos Erin can store 1. We know 1 GB = 1024 MB (since 1 GB = 1024 megabytes). 2. Each photo size = 3.6 MB. 3. Number of photos = Total memory / Size per photo = $$\frac{1024}{3.6}$$. 4. Calculate: $$\frac{1024}{3.6} \approx 284.44$$. 5. Since Erin cannot store a fraction of a photo, she can store approximately **284 photos**. --- ### Problem 2: Suggested photo size for Sue 1. Total memory = 32 GB = 32 \times 1024 MB = 32768 MB. 2. Number of photos desired = 13000. 3. Photo size = Total memory / Number of photos = $$\frac{32768}{13000}$$ MB. 4. Calculate: $$\frac{32768}{13000} \approx 2.52$$ MB per photo. 5. Sue should use photos of size about **2.5 MB** to store 13000 photos on a 32 GB card. --- ### Matching cards A to E with i to v Convert all sizes to the same unit (meters to micrometers or nanometers): - 1 m = 1,000,000 μm = 1,000,000,000 nm Card A: Dust mite = 0.0002 m = 0.0002 \times 1,000,000 μm = 200 μm Card B: Bacterium = 0.000002 m = 2 μm Card C: Virus = 0.0000001 m = 0.1 μm = 100 nm Card D: Animal cell = 0.00002 m = 20 μm Card E: Plant cell = 0.0001 m = 100 μm Now match: - i: 100 nm = 0.1 μm → matches Virus (C) - ii: 20 μm → matches Animal cell (D) - iii: 200 μm → matches Dust mite (A) - iv: 100 μm → matches Plant cell (E) - v: 2 μm → matches Bacterium (B) --- **Final answers:** - Erin can store approximately **284 photos**. - Sue should use photos of size about **2.5 MB**. - Matching cards: - A → iii - B → v - C → i - D → ii - E → iv