Pattern Arithmetic
1. **Problem statement:**
(i) Given the pattern ৮, ১৩, ১৮, ২৩, ... or numerically 8, 13, 18, 23, ...
(ii) The algebraic sequence ৫x + ২ or 5x + 2.
(a) Draw the 3rd and 4th terms of the sequence ৪x + ১ or 4x + 1.
(b) Explain which algebraic sequence the pattern (i) supports.
(c) Find how many squares are needed for the first 11 terms of (ii) 5x + 2.
2. For a rectangular field with 3 processors and grass laying cost of 1822.50 at rate 7.50 per meter:
(a) Find the length of the rectangular field using the processor measure 8 meters.
(b) Find the length and width of the rectangular field.
(c) Find how many 25 meter border girders are needed to make a square field of equal area.
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2. **Step-by-step solutions:**
**(1)(a) Find 3rd and 4th terms of 4x + 1:**
For x=3: $$4(3) + 1 = 12 + 1 = 13$$
For x=4: $$4(4) + 1 = 16 + 1 = 17$$
So, 3rd term is 13 and 4th term is 17.
**(1)(b) Identify the sequence pattern matching 8, 13, 18, 23,...**
The pattern increases by 5 each time (common difference = 5), so it is an arithmetic sequence.
General term: $$a_n = a_1 + (n - 1)d = 8 + (n-1)5 = 5n + 3$$
Compare with given sequence 5x + 2; ours is 5n + 3, close but different by 1. The pattern fits better to $$5n + 3$$.
**(1)(c) Number of squares needed for first 11 terms of 5x + 2:**
This sequence: $$a_n = 5n + 2$$
Sum of first 11 terms:
$$S_{11} = \sum_{n=1}^{11} (5n + 2) = 5 \sum_{n=1}^{11} n + 2 \times 11 = 5 \times \frac{11 \times 12}{2} + 22 = 5 \times 66 + 22 = 330 + 22 = 352$$
So, 352 squares are needed.
**(2)(a) Find length using 3 processors of 8 m each:**
Total length = number of processors × length per processor = $$3 \times 8 = 24$$ meters.
**(2)(b) Find length and width given total cost 1822.50 and cost rate 7.50 per meter:**
Total cost = perimeter × cost per meter
Perimeter $$P = \frac{1822.50}{7.50} = 243$$ meters.
We know length $$L = 24$$ meters.
Perimeter $$P = 2(L + W)$$ so,
$$243 = 2(24 + W) \Rightarrow 24 + W = 121.5 \Rightarrow W = 121.5 - 24 = 97.5$$
Width $$W = 97.5$$ meters.
**(2)(c) Find number of 25m border girders to build square field with equal area:**
Area of rectangular field $$A = L \times W = 24 \times 97.5 = 2340$$ m²
Side of square field $$s = \sqrt{2340} \approx 48.37$$ meters.
Number of 25 m girders per side:
$$\text{girders per side} = \lceil \frac{48.37}{25} \rceil = 2$$
Total girders for 4 sides:
$$4 \times 2 = 8$$
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**Final answers:**
(a) 3rd term = 13, 4th term = 17
(b) Pattern fits arithmetic sequence $$5n + 3$$
(c) Squares needed for first 11 terms = 352
(2)(a) Length = 24 m
(2)(b) Width = 97.5 m
(2)(c) Number of girders needed = 8