Mixed Math Problems
1. **Write 324 as a product of powers of its prime factors.**
Step 1: Find prime factors of 324.
324 ÷ 2 = 162
162 ÷ 2 = 81
81 ÷ 3 = 27
27 ÷ 3 = 9
9 ÷ 3 = 3
3 ÷ 3 = 1
Step 2: Count the powers.
Number of 2's: 2
Number of 3's: 4
Step 3: Write as product of prime powers:
$$324 = 2^2 \times 3^4$$
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2. **Find the square root of** $$A = 2^4 \times 3^6 \times 5^2 \times 7^4$$
Step 1: Use the property $$\sqrt{a^m} = a^{m/2}$$.
Step 2: Apply square root to each prime power:
$$\sqrt{A} = 2^{4/2} \times 3^{6/2} \times 5^{2/2} \times 7^{4/2} = 2^2 \times 3^3 \times 5^1 \times 7^2$$
Step 3: Calculate numeric value:
$$2^2 = 4, \quad 3^3 = 27, \quad 5^1 = 5, \quad 7^2 = 49$$
$$\sqrt{A} = 4 \times 27 \times 5 \times 49 = 26460$$
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3. **Calculate and simplify:** $$\frac{11}{45} \times \frac{15}{22}$$
Step 1: Multiply numerators and denominators:
$$\frac{11 \times 15}{45 \times 22} = \frac{165}{990}$$
Step 2: Simplify fraction by dividing numerator and denominator by 15:
$$\frac{165 \div 15}{990 \div 15} = \frac{11}{66}$$
Step 3: Simplify further by dividing numerator and denominator by 11:
$$\frac{11 \div 11}{66 \div 11} = \frac{1}{6}$$
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4. **Calculate:** $$\frac{1}{2} \div \frac{3}{5}$$
Step 1: Division of fractions is multiplication by reciprocal:
$$\frac{1}{2} \times \frac{5}{3} = \frac{5}{6}$$
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5. **Calculate:** $$4.23 \times 6.7$$ using written method
Step 1: Multiply as integers ignoring decimals:
$$423 \times 67 = 28341$$
Step 2: Count decimal places: 2 (4.23) + 1 (6.7) = 3
Step 3: Place decimal point 3 places from right:
$$28.341$$
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6. **Calculate:** $$\sqrt[3]{\frac{1000}{2}} + 3^2$$
Step 1: Simplify inside cube root:
$$\frac{1000}{2} = 500$$
Step 2: Calculate cube root:
$$\sqrt[3]{500} = \sqrt[3]{125 \times 4} = 5 \times \sqrt[3]{4} \approx 5 \times 1.5874 = 7.937$$
Step 3: Calculate $$3^2 = 9$$
Step 4: Add results:
$$7.937 + 9 = 16.937$$
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7. **Calculate:** $$100 - (6 - 4)^5$$
Step 1: Simplify inside parentheses:
$$6 - 4 = 2$$
Step 2: Calculate power:
$$2^5 = 32$$
Step 3: Subtract:
$$100 - 32 = 68$$
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8. **Expand and simplify:** $$7(4 - 3x) - 5x(2 + 5x)$$
Step 1: Expand terms:
$$7 \times 4 = 28$$
$$7 \times (-3x) = -21x$$
$$-5x \times 2 = -10x$$
$$-5x \times 5x = -25x^2$$
Step 2: Combine all:
$$28 - 21x - 10x - 25x^2 = 28 - 31x - 25x^2$$
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9. **Calculate:** $$\frac{a^3 + 7}{1 - b^2}$$ when $$a=2$$ and $$b=-4$$
Step 1: Calculate numerator:
$$a^3 + 7 = 2^3 + 7 = 8 + 7 = 15$$
Step 2: Calculate denominator:
$$1 - b^2 = 1 - (-4)^2 = 1 - 16 = -15$$
Step 3: Calculate value:
$$\frac{15}{-15} = -1$$
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10. **Factorise fully:** $$30x^2p + 18x^2$$
Step 1: Find common factors:
Common factor is $$6x^2$$
Step 2: Factor out:
$$6x^2(5p + 3)$$
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11. **Solve for x:** $$6x - 2 = 4x + 14$$
Step 1: Subtract $$4x$$ from both sides:
$$6x - 4x - 2 = 14$$
$$2x - 2 = 14$$
Step 2: Add 2 to both sides:
$$2x = 16$$
Step 3: Divide both sides by 2:
$$x = 8$$
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12. **Solve for y:** $$5(y + 6) = 3(y + 12)$$
Step 1: Expand both sides:
$$5y + 30 = 3y + 36$$
Step 2: Subtract $$3y$$ from both sides:
$$2y + 30 = 36$$
Step 3: Subtract 30 from both sides:
$$2y = 6$$
Step 4: Divide both sides by 2:
$$y = 3$$
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13. **Cost to tile bathroom wall:**
Step 1: Calculate wall area:
$$4.5 \times 6 = 27 \text{ m}^2 = 270000 \text{ cm}^2$$
Step 2: Tile area per tile:
$$900 \text{ cm}^2$$
Step 3: Number of tiles needed:
$$\frac{270000}{900} = 300$$
Step 4: Number of packs (10 tiles per pack):
$$\frac{300}{10} = 30$$
Step 5: Cost per pack:
7.50
Step 6: Total cost:
$$30 \times 7.50 = 225$$
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14. **Area of shape (rectangle + 2 isosceles triangles):**
Step 1: Rectangle area:
$$8 \times 4 = 32 \text{ cm}^2$$
Step 2: Triangle base = 4 cm (height of rectangle), height unknown but assume equal to 4 cm (isosceles with base 4 and height 4 for calculation)
Triangle area:
$$\frac{1}{2} \times 4 \times 4 = 8 \text{ cm}^2$$
Step 3: Two triangles area:
$$2 \times 8 = 16 \text{ cm}^2$$
Step 4: Total area:
$$32 + 16 = 48 \text{ cm}^2$$
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15. **Volume of cuboid given face areas:**
Step 1: Let dimensions be $$l, w, h$$.
Given:
$$lw = 12$$
$$lh = 20$$
$$wh = 15$$
Step 2: Multiply all:
$$(lw)(lh)(wh) = 12 \times 20 \times 15 = 3600$$
Step 3: Left side equals:
$$(lwh)^2 = 3600$$
Step 4: Take square root:
$$lwh = \sqrt{3600} = 60$$
Step 5: Volume = $$lwh = 60$$
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16. **Distance from home to school:**
From graph, distance at 10 minutes is 400 m, at 20 minutes still 400 m, at 30 minutes 700 m.
Distance from home to school = 700 m
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17. **Describe motion from 10 to 20 minutes:**
Distance remains constant at 400 m, so Iman is stationary or resting.
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18. **Time to walk to school:**
From 0 to 30 minutes, total distance 700 m.
Time taken = 30 minutes
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19. **Average speed:**
$$\text{Speed} = \frac{\text{Distance}}{\text{Time}} = \frac{700}{30} \approx 23.33 \text{ m/min}$$
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20. **Harbour water depth graph:**
a) Maximum depth is approximately 8 m
b) Minimum depth is approximately 4 m
c) Time between successive high tides (from 3 to 15 hours) = 12 hours
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**Total questions answered: 20**