1. Stating the problem: We need to calculate the amount of nitrogen (N), phosphorus (P), and potassium (K) received by a single rice plant. 2. Given data: - Fertilizer recommendation: 120 kg N, 60 kg P\textsubscript{2}O\textsubscript{5}, 60 kg K\textsubscript{2}O per some area. - Plant spacing: 20 cm × 20 cm. - Plants per hill: 3. - Percentage of P in P\textsubscript{2}O\textsubscript{5} = 44%. - Percentage of K in K\textsubscript{2}O = 83%. 3. Calculate number of plants per square meter: Since plant spacing is 20 cm × 20 cm, the area per plant is $$0.2\ \text{m} \times 0.2\ \text{m} = 0.04\ \text{m}^2$$. Number of hills per square meter = $$\frac{1}{0.04} = 25$$. Number of plants per square meter = $$25 \times 3 = 75$$. 4. Convert P\textsubscript{2}O\textsubscript{5} and K\textsubscript{2}O to P and K: - Amount of P = $$60 \times 0.44 = 26.4\ \text{kg}$$. - Amount of K = $$60 \times 0.83 = 49.8\ \text{kg}$$. 5. Calculate the amount of nutrients per single plant: - N per plant = $$\frac{120}{75} = 1.6\ \text{kg}$$. - P per plant = $$\frac{26.4}{75} = 0.352\ \text{kg}$$. - K per plant = $$\frac{49.8}{75} = 0.664\ \text{kg}$$. Final answer: A single plant receives approximately $$1.6\ \text{kg}$$ of nitrogen, $$0.352\ \text{kg}$$ of phosphorus, and $$0.664\ \text{kg}$$ of potassium.