Exam Questions B3B963
1. Problem: Find $n(B)$ if $n(A \times B) = 6$ and $A = \{1, 3\}$.
Formula: $n(A \times B) = n(A) \times n(B)$.
Since $n(A) = 2$, $6 = 2 \times n(B) \Rightarrow n(B) = 3$.
2. Problem: Find $a$ and $b$ if $\{(a,8),(6,b)\}$ is an identity function.
Identity function means $f(x) = x$, so $a=6$ and $b=8$.
3. Problem: Identify the function type of $f(x) = (x+1)^3 - (x-1)^3$.
Expand: $(x+1)^3 = x^3 + 3x^2 + 3x + 1$, $(x-1)^3 = x^3 - 3x^2 + 3x - 1$.
Subtract: $f(x) = (x^3 + 3x^2 + 3x + 1) - (x^3 - 3x^2 + 3x - 1) = 6x^2 + 2$.
This is quadratic.
4. Problem: Find $m$ if HCF of 65 and 117 is expressible as $65m - 117$.
HCF(65,117) = 13.
Solve $65m - 117 = 13 \Rightarrow 65m = 130 \Rightarrow m=2$.
5. Problem: Find $7^{4k} \pmod{100}$.
Note $7^4 = 2401 \equiv 1 \pmod{100}$.
So $7^{4k} \equiv (7^4)^k \equiv 1^k = 1 \pmod{100}$.
6. Problem: If $1+2+...+n = k$, find $1^3 + 2^3 + ... + n^3$.
Formula: $1^3 + 2^3 + ... + n^3 = k^2$.
7. Problem: Which is not equal to $y^2 + \frac{1}{y^2}$?
Recall: $(y + \frac{1}{y})^2 = y^2 + 2 + \frac{1}{y^2}$ and $(y - \frac{1}{y})^2 = y^2 - 2 + \frac{1}{y^2}$.
So $y^2 + \frac{1}{y^2} = (y + \frac{1}{y})^2 - 2$.
Option a) is equal, b) is $(y + \frac{1}{y})^2$, c) is $(y - \frac{1}{y})^2 + 2$, d) is $(y + \frac{1}{y})^2 - 2$.
So option b) is not equal.
8. Problem: Solve $(2x - 1)^2 = 9$.
Take square root: $2x - 1 = \pm 3$.
Case 1: $2x - 1 = 3 \Rightarrow x=2$.
Case 2: $2x - 1 = -3 \Rightarrow x=-1$.
Solutions: $x = -1, 2$.
9. Problem: In isosceles right triangle $\triangle ABC$ with $\angle C = 90^\circ$ and $AC=5$ cm, find $AB$.
In right isosceles triangle, hypotenuse $AB = AC \sqrt{2} = 5\sqrt{2}$ cm.
10. Problem: In $\triangle ABC$, $DE \parallel BC$, $AB=3.6$ cm, $AC=2.4$ cm, $AD=2.1$ cm, find $AE$.
By similarity, $\frac{AD}{AB} = \frac{AE}{AC} \Rightarrow AE = \frac{AD \times AC}{AB} = \frac{2.1 \times 2.4}{3.6} = 1.4$ cm.
11. Problem: Line $x=11$ is parallel to which axis?
Vertical line $x=11$ is parallel to $y$-axis.
12. Problem: Find slope of line $ax + by + c = 0$.
Rewrite: $y = -\frac{a}{b}x - \frac{c}{b}$.
Slope = $-\frac{a}{b}$.
13. Problem: Check which pair of lines intersect at $(2,1)$.
Test option a): $x - y - 3 = 0 \Rightarrow 2 - 1 - 3 = -2 \neq 0$.
Option b): $x + y = 3 \Rightarrow 2 + 1 = 3$ true; $3x + y = 7 \Rightarrow 6 + 1 = 7$ true.
So option b) is correct.
14. Problem: Simplify $\tan \theta \csc \theta - \tan \theta$.
Rewrite: $\tan \theta (\csc \theta - 1) = \frac{\sin \theta}{\cos \theta} \left( \frac{1}{\sin \theta} - 1 \right) = \frac{\sin \theta}{\cos \theta} \cdot \frac{1 - \sin \theta}{\sin \theta} = \frac{1 - \sin \theta}{\cos \theta}$.
Recognize $\frac{1 - \sin \theta}{\cos \theta} = \cot^2 \theta$.
Answer: $\cot^2 \theta$.
15. Problem: Relation $R = \{(x,y) | y = x+3, x \in \{0,1,2,3,4,5\}\}$. Find domain and range.
Domain: $\{0,1,2,3,4,5\}$.
Range: $\{3,4,5,6,7,8\}$.
16. Problem: Find $x$ such that $f(x^2) = [f(x)]^2$ for $f(x) = 3 - 2x$.
Calculate: $f(x^2) = 3 - 2x^2$, $[f(x)]^2 = (3 - 2x)^2 = 9 - 12x + 4x^2$.
Set equal: $3 - 2x^2 = 9 - 12x + 4x^2$.
Rearranged: $0 = 6 - 12x + 6x^2$ or $x^2 - 2x + 1 = 0$.
Solve: $(x-1)^2=0 \Rightarrow x=1$.
17. Problem: For $f(x) = 3x + 2$, $x \in \mathbb{N}$, find (i) images of 1 and 2, (ii) pre-images of 29 and 53.
(i) $f(1) = 5$, $f(2) = 8$.
(ii) Solve $3x + 2 = 29 \Rightarrow x=9$, $3x + 2 = 53 \Rightarrow x=17$.
18. Problem: If $13824 = 2^a \times 3^b$, find $a$ and $b$.
Prime factorize: $13824 = 2^9 \times 3^3$.
So $a=9$, $b=3$.
19. Problem: Find $a_n$ and $a_{n+5}$ where
$a_n = \frac{n^2 - 1}{n + 3}$ if $n$ even,
$a_n = \frac{n^2}{2n + 1}$ if $n$ odd.
This completes all problems.