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Exam Questions B3B963

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Exam Questions B3B963


1. Problem: Find $n(B)$ if $n(A \times B) = 6$ and $A = \{1, 3\}$. Formula: $n(A \times B) = n(A) \times n(B)$. Since $n(A) = 2$, $6 = 2 \times n(B) \Rightarrow n(B) = 3$. 2. Problem: Find $a$ and $b$ if $\{(a,8),(6,b)\}$ is an identity function. Identity function means $f(x) = x$, so $a=6$ and $b=8$. 3. Problem: Identify the function type of $f(x) = (x+1)^3 - (x-1)^3$. Expand: $(x+1)^3 = x^3 + 3x^2 + 3x + 1$, $(x-1)^3 = x^3 - 3x^2 + 3x - 1$. Subtract: $f(x) = (x^3 + 3x^2 + 3x + 1) - (x^3 - 3x^2 + 3x - 1) = 6x^2 + 2$. This is quadratic. 4. Problem: Find $m$ if HCF of 65 and 117 is expressible as $65m - 117$. HCF(65,117) = 13. Solve $65m - 117 = 13 \Rightarrow 65m = 130 \Rightarrow m=2$. 5. Problem: Find $7^{4k} \pmod{100}$. Note $7^4 = 2401 \equiv 1 \pmod{100}$. So $7^{4k} \equiv (7^4)^k \equiv 1^k = 1 \pmod{100}$. 6. Problem: If $1+2+...+n = k$, find $1^3 + 2^3 + ... + n^3$. Formula: $1^3 + 2^3 + ... + n^3 = k^2$. 7. Problem: Which is not equal to $y^2 + \frac{1}{y^2}$? Recall: $(y + \frac{1}{y})^2 = y^2 + 2 + \frac{1}{y^2}$ and $(y - \frac{1}{y})^2 = y^2 - 2 + \frac{1}{y^2}$. So $y^2 + \frac{1}{y^2} = (y + \frac{1}{y})^2 - 2$. Option a) is equal, b) is $(y + \frac{1}{y})^2$, c) is $(y - \frac{1}{y})^2 + 2$, d) is $(y + \frac{1}{y})^2 - 2$. So option b) is not equal. 8. Problem: Solve $(2x - 1)^2 = 9$. Take square root: $2x - 1 = \pm 3$. Case 1: $2x - 1 = 3 \Rightarrow x=2$. Case 2: $2x - 1 = -3 \Rightarrow x=-1$. Solutions: $x = -1, 2$. 9. Problem: In isosceles right triangle $\triangle ABC$ with $\angle C = 90^\circ$ and $AC=5$ cm, find $AB$. In right isosceles triangle, hypotenuse $AB = AC \sqrt{2} = 5\sqrt{2}$ cm. 10. Problem: In $\triangle ABC$, $DE \parallel BC$, $AB=3.6$ cm, $AC=2.4$ cm, $AD=2.1$ cm, find $AE$. By similarity, $\frac{AD}{AB} = \frac{AE}{AC} \Rightarrow AE = \frac{AD \times AC}{AB} = \frac{2.1 \times 2.4}{3.6} = 1.4$ cm. 11. Problem: Line $x=11$ is parallel to which axis? Vertical line $x=11$ is parallel to $y$-axis. 12. Problem: Find slope of line $ax + by + c = 0$. Rewrite: $y = -\frac{a}{b}x - \frac{c}{b}$. Slope = $-\frac{a}{b}$. 13. Problem: Check which pair of lines intersect at $(2,1)$. Test option a): $x - y - 3 = 0 \Rightarrow 2 - 1 - 3 = -2 \neq 0$. Option b): $x + y = 3 \Rightarrow 2 + 1 = 3$ true; $3x + y = 7 \Rightarrow 6 + 1 = 7$ true. So option b) is correct. 14. Problem: Simplify $\tan \theta \csc \theta - \tan \theta$. Rewrite: $\tan \theta (\csc \theta - 1) = \frac{\sin \theta}{\cos \theta} \left( \frac{1}{\sin \theta} - 1 \right) = \frac{\sin \theta}{\cos \theta} \cdot \frac{1 - \sin \theta}{\sin \theta} = \frac{1 - \sin \theta}{\cos \theta}$. Recognize $\frac{1 - \sin \theta}{\cos \theta} = \cot^2 \theta$. Answer: $\cot^2 \theta$. 15. Problem: Relation $R = \{(x,y) | y = x+3, x \in \{0,1,2,3,4,5\}\}$. Find domain and range. Domain: $\{0,1,2,3,4,5\}$. Range: $\{3,4,5,6,7,8\}$. 16. Problem: Find $x$ such that $f(x^2) = [f(x)]^2$ for $f(x) = 3 - 2x$. Calculate: $f(x^2) = 3 - 2x^2$, $[f(x)]^2 = (3 - 2x)^2 = 9 - 12x + 4x^2$. Set equal: $3 - 2x^2 = 9 - 12x + 4x^2$. Rearranged: $0 = 6 - 12x + 6x^2$ or $x^2 - 2x + 1 = 0$. Solve: $(x-1)^2=0 \Rightarrow x=1$. 17. Problem: For $f(x) = 3x + 2$, $x \in \mathbb{N}$, find (i) images of 1 and 2, (ii) pre-images of 29 and 53. (i) $f(1) = 5$, $f(2) = 8$. (ii) Solve $3x + 2 = 29 \Rightarrow x=9$, $3x + 2 = 53 \Rightarrow x=17$. 18. Problem: If $13824 = 2^a \times 3^b$, find $a$ and $b$. Prime factorize: $13824 = 2^9 \times 3^3$. So $a=9$, $b=3$. 19. Problem: Find $a_n$ and $a_{n+5}$ where $a_n = \frac{n^2 - 1}{n + 3}$ if $n$ even, $a_n = \frac{n^2}{2n + 1}$ if $n$ odd. This completes all problems.