Cbse 10Th Questions 2E2915
1. Problem: Find the other number if LCM is 182, HCF is 13, and one number is 26.
Formula: Product of two numbers = LCM × HCF
Calculation: Let the other number be $x$.
$26 \times x = 182 \times 13$
$x = \frac{182 \times 13}{26} = 91$
Answer: (d) 91
2. Problem: Find quadratic polynomial with sum of zeroes = 0 and product = $\sqrt{5}$.
Formula: Polynomial is $x^2 - (sum) x + product = 0$
Here, sum = 0, product = $\sqrt{5}$
Polynomial: $x^2 + \sqrt{5} = 0$
Answer: (c) $x^2 - \sqrt{5}$
3. Problem: System $kx - y = 2$ and $6x - 2y = 3$ has unique solution when?
Rule: Unique solution if determinant $\neq 0$.
Determinant: $\begin{vmatrix} k & -1 \\ 6 & -2 \end{vmatrix} = k(-2) - (-1)(6) = -2k + 6$
Set $\neq 0$: $-2k + 6 \neq 0 \Rightarrow k \neq 3$
Answer: (d) $k \neq 3$
4. Problem: One root of $2x^2 + kx - 6 = 0$ is 2, find $k$.
Substitute root:
$2(2)^2 + k(2) - 6 = 0 \Rightarrow 8 + 2k - 6 = 0 \Rightarrow 2k + 2 = 0 \Rightarrow k = -1$
Answer: (b) -1
5. Problem: In AP, $d = -4$, $n=7$, $a_n=4$, find $a$.
Formula: $a_n = a + (n-1)d$
$4 = a + 6(-4) \Rightarrow 4 = a - 24 \Rightarrow a = 28$
Answer: (d) 28
6. Problem: $k-1$, $k+3$, $3k-1$ in AP, find $k$.
AP condition: $2 \times (middle) = first + last$
$2(k+3) = (k-1) + (3k-1)$
$2k + 6 = 4k - 2 \Rightarrow 6 + 2 = 4k - 2k \Rightarrow 8 = 2k \Rightarrow k = 4$
Answer: (a) 4
7. Problem: Find ratio in which x-axis divides join of $P(2,-3)$ and $Q(5,6)$.
Let ratio be $m:n$.
Since point lies on x-axis, y-coordinate = 0.
Using section formula for y:
$\frac{m \times 6 + n \times (-3)}{m + n} = 0$
$6m - 3n = 0 \Rightarrow 2m = n \Rightarrow m:n = 1:2$
Answer: (b) 1:2
8. Problem: Which is NOT similarity criterion?
Options: AA, SAS, AAA, RHS
AAA is not a valid similarity criterion (it is for congruence).
Answer: (c) AAA
9. Problem: Find center of circle with diameter ends $(a,b)$ and $(-a,-b)$.
Center is midpoint:
$\left( \frac{a + (-a)}{2}, \frac{b + (-b)}{2} \right) = (0,0)$
Answer: (a) (0,0)