1. The problem asks to find the norm (or magnitude) of vector $v$ for part (a) where $v = (1, -1)$. 2. The norm of a vector $v = (x, y)$ in 2D is given by the formula: $$\|v\| = \sqrt{x^2 + y^2}$$ 3. Substitute the components of $v$: $$\|v\| = \sqrt{1^2 + (-1)^2} = \sqrt{1 + 1} = \sqrt{2}$$ 4. Therefore, the norm of $v = (1, -1)$ is $\sqrt{2}$.